F(t)=0.25t^2+65

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Solution for F(t)=0.25t^2+65 equation: 



(F)=0.25F^2+65

We move all terms to the left:

(F)-(0.25F^2+65)=0

We get rid of parentheses

-0.25F^2+F-65=0

a = -0.25; b = 1; c = -65;
Δ = b2-4ac
Δ = 12-4·(-0.25)·(-65)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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